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Which of the following are solutions to the equation below 6x-2x+36=5x^2+10x

User Dleep
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1 Answer

3 votes

Answer:

Two real solutions

x =(6-√756)/-10=3/-5+3/5√ 21 = 2.150

x =(6+√756)/-10=3/-5-3/5√ 21 = -3.350

Explanation:

Solve Quadratic Equation using the Quadratic Formula

4.3 Solving -5x2-6x+36 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

x = ————————

2A

In our case, A = -5

B = -6

C = 36

Accordingly, B2 - 4AC =

36 - (-720) =

756

Applying the quadratic formula :

6 ± √ 756

x = —————

-10

Can √ 756 be simplified ?

Yes! The prime factorization of 756 is

2•2•3•3•3•7

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 756 = √ 2•2•3•3•3•7 =2•3•√ 21 =

± 6 • √ 21

√ 21 , rounded to 4 decimal digits, is 4.5826

So now we are looking at:

x = ( 6 ± 6 • 4.583 ) / -10

Two real solutions:

x =(6+√756)/-10=3/-5-3/5√ 21 = -3.350

or:

x =(6-√756)/-10=3/-5+3/5√ 21 = 2.150

Two solutions were found :

x =(6-√756)/-10=3/-5+3/5√ 21 = 2.150

x =(6+√756)/-10=3/-5-3/5√ 21 = -3.350

User Shamese
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