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How many liters of a 0.2300 M potassium chloride solution contain 0.250 moles of potassium chloride

User Kevork
by
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2 Answers

5 votes

Answer:

1.087L

Step-by-step explanation:

Volume= 0.25/0.23 = 1.087L

User Fuelusumar
by
5.9k points
5 votes

Answer:

1.087L

Step-by-step explanation:

No of mole = concentrate × volume

Volume= 0.25/0.23 = 1.087L

User Hassaan Tauqir
by
5.5k points