Question

22 g gaz ocupa la presiunea de 15 atmosfere si temperatura de 0 grade celsius , un volum de 0,7462 litri. Care este gazul : A. CO, B. CO2, C. N2 D. NH3 Alegeti raspunsul corect.

Answer 1

CO₂. Option B.

Step-by-step explanation:

We can use the Ideal Gases Law to solve this question

Formula: P . V = n. R . T

First of all, we convert the T° from °C to K

T°C + 273 → 0°C + 273 = 273K

Let's replace data: 15 atm . 0.7462 L = n . 0.082 L.atm/mol.K . 273K

15 atm . 0.7462 L / (0.082 L.atm/mol.K . 273K) = n

0.500 mol = n

These moles are the amount for 22 g of gas. Let's determine the molar mass to find out the gas → molar mass = g/mol

22 g /0.5m = 44g/mol

This molar mass corresponds to CO₂