Answer:
mass NH3 = 11.264 g
mass N2 = 9.264 g
Step-by-step explanation:
balanced reaction:
∴ mass H2 = 2.00 g
∴ molar mass H2 = 2.016 g/mol
∴ molar mass N2 = 28.0134 g/mol
∴ molar mass NH3 = 17.031 g/mol
⇒ mol H2 = (2.00 g)*(mol/2.016 g) = 0.992 mol
⇒ mol NH3 = (0.992 mol H2)*(2 mol NH3/3 mol H2) = 0.6614 mol
⇒ mass NH3 = (0.6614 mol)*(17.031 g/mol) = 11.264 g
⇒ mol N2 = (0.6614 mol NH3)*(mol N2/2 mol NH3) = 0.3307 mol
⇒ mass N2 = (0.3307 mol)*(28.0134 g/mol) = 9.264 g