Answer:
Rl≤ 864 ohms
Step-by-step explanation:
ω=2πf⇒ f=ω/2π
ω=27000
fc=R/2πL
27000/2π= R/(2π×0.004)
R=108 ohms
For terminated RL filters, cutoff frequency is given by
ω=(R || Rl)/ L
24000 ≥ (108 || Rl)/ 0.004
96 ≥ 108Rl/(108+Rl)
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