Question

How many kJ are required to melt 100 grams of water?

Answer 1

33.4 kj

Step-by-step explanation:

Given data:

Mass of water = 100 g

Kj required to melt = ?

Solution:

Formula:

q = mHf

Hf = heat of fusion

Heat of fusion of water = 333.55 /g

Now we will put the values in formula.

q = 100 g × 333.55 j/ 1g

q = 33350 j

Jolue to kj conversion.

33350 j × 1kj / 1000 j

33.4 kj