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What’s the volume of 2.3 moles of At at STP

User JPvdMerwe
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1 Answer

6 votes

Answer:


0.052 m^3

Step-by-step explanation:

We can solve this problem by using the ideal gas equation, which states that:


pV=nRT

where

p is the gas pressure

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

In this problem, we have:

n = 2.3 mol of the gas

The gas is in STP condition, so:

T = 273.15 K is the temperature


p=1.013\cdot 10^5 Pa is the pressure


R=8.31 J/mol K is the gas constant

Solving for V, we find the volume:


V=(nRT)/(p)=((2.3)(8.31)(273.15))/(1.013\cdot 10^5)=0.052 m^3

User Ricky McMaster
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