Question

What’s the volume of 2.3 moles of At at STP

Answer 1

`0.052 m^3`

Step-by-step explanation:

We can solve this problem by using the ideal gas equation, which states that:

`pV=nRT`

where

p is the gas pressure

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

In this problem, we have:

n = 2.3 mol of the gas

The gas is in STP condition, so:

T = 273.15 K is the temperature

`p=1.013\cdot 10^5 Pa` is the pressure

`R=8.31 J/mol K` is the gas constant

Solving for V, we find the volume:

`V=(nRT)/(p)=((2.3)(8.31)(273.15))/(1.013\cdot 10^5)=0.052 m^3`