Answer:
The motional emf generated between the ends of the wire is
7341 V
Step-by-step explanation:
Given :
Length of satellite
m
Magnetic field
T
Speed of shuttle
![v = 5.01 * 10^(3) (m)/(s)](https://img.qammunity.org/2021/formulas/physics/college/2mhopo47mb8z418r1onnwwcm2vn8xo6cro.png)
The emf generated between the ends of the wire is given by,
Induced emf =
![Blv\sin \theta](https://img.qammunity.org/2021/formulas/physics/college/18jj3xpu6xnfa9n6mrvyqi7fwsmsykec8p.png)
Where
![\sin 90 = 1](https://img.qammunity.org/2021/formulas/physics/high-school/kyic9euggq14m0l2f1ibm3nzvq319xd2ri.png)
emf =
![5.16 * 10^(-5) * 5.01 * 10^(3) * 2.84 * 10^(4)](https://img.qammunity.org/2021/formulas/physics/college/slkurm07joxvss6a6o6pjlot309we5v48f.png)
emf ≅
V
Therefore, the motional emf generated between the ends of the wire is
7341 V