Question

At a certain temperature, the equilibrium constant, K c , is 0.00376 for the reaction Cl 2 ( g ) − ⇀ ↽ − 2 Cl ( g ) A. If 3.45 g Cl 2 is placed in a 3.50 L flask at this temperature, what are the equilibrium concentrations of Cl 2 and Cl ?

Answer 1

Equilibrium concentration of Cl₂ = 0.013 molar

Equilibrium concentration of Cl = 0.0072 molar

Step-by-step explanation:

Cl ₂ ( g ) ⇄ 2 Cl ( g )

No. of moles of Cl₂(g) =
`(Mass given)/(Molar mass)`

=
`(3.45)/(71)`

= 0.048 mole

Concentration of Cl₂ =
`(0.048 )/(3.5)` M = 0.013 molar

From the above equation we get

`K_(c)` =
`([Cl]^(2) )/([Cl_(2) ])`

[Cl]² = Kc X [Cl₂]

= 0.00376 x 0.013

= 5.22 x 10⁻⁵ molar

[Cl] = 0.0072 molar