Question

Two obiect accumulated a charge of

4.5 uc and another a charge n. 2. 8
HC. These two objects are separated
by a distance of 2.5 cm. Calculate the
magnitude of the electric force
between these two objects.
A.181.24 N
B.4.53 N
C. 1.81 x 10^14 N
D. 2.02 x 10^-8 N

Answer 1

A. 181.24 N

Step-by-step explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

`F=k(q_1 q_2)/(r^2)`

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

`q_1=4.5\mu C=4.5\cdot 10^(-6)C` is the magnitude of the 1st charge

`q_2=2.8\mu C=2.8\cdot 10^(-6)C` is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

`F=((9\cdot 10^9)(4.5\cdot 10^(-6))(2.8\cdot 10^(-6)))/((0.025)^2)=181.44 N`

So, the closest answer is

A) 181.24 N