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22. A line passes through (-6,-1) and (3, 2).
What is the equation of the line?

User Merav
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Answer: y = 1/3x + 1 or y = 2 + 1/3(x-3)

Step-by-step explanation: Solve for the slope: (y2-y1) / (x2-x1), in this case, 2 - (-1) / 3 - (-6) = 3/9 = 1/3. Then, write it in point-slope form:

y = y1 + b(x-x1), in this case,

y = 2 + 1/3(x-3) or y = -1 + 1/3(x-(-6). To convert to intercept form (y = a +bx), distribute the 1/3 so that it's y = 2 + 1/3x - 1, then combine like terms to get y = 1 + 1/3x.

User Fatuhoku
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