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How many moles of a gas will 700 m hold at -100 oC and 86 atm?

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0.23 moles of a gas will 700 m hold at -100 oC and 86 atm.

Step-by-step explanation:

given that:

volume = 700 ml OR 0.7 Litre (for converting into litre it is divided with 1000 as 1 litre = 1000ml)

temperature = -100 degrees OR 173.15 K

pressure = 86 atm

R = 0.082057 L atm mol-1K-1

n=?

It is known that when Volume is taken in litres, pressure in atm, and temperature in Kelvin then R= 0.082057 L atm mol-1K-1,

From the formula for ideal gas:

PV = nRT

putting the values in the formula:

n =
(RT)/(PV)

=
(0.0820507 X 173.15)/(0.7 X 86)

= 0.23 moles of the gas will be required.

User Sebastian Noack
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