The line y = 7x + 2 perpendicular to the
.
Solution:
Equation of one line:
![y=7 x+2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4s5o2jo39c2awp74u5ebr01n9pve6ojyi4.png)
Slope of this line:
![m_1=7](https://img.qammunity.org/2021/formulas/mathematics/middle-school/c6yupz8ktb7jzk36shvzldk13o9wnkueet.png)
Equation of another line:
![$ y=-(1)/(7) x+12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kvjhhyewht1zf47312wlxzjexg8jkirnz2.png)
Slope of this line:
![$m_2=-(1)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yleypobujp5jyry3he5pxn6l122d6j4qzz.png)
If two lines are perpendicular, then the product of their slope is -1.
![$m_1 * m_2=7 *(-1)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/splqheja07u87l8lkss11yljovucj2n21v.png)
Both 7's get canceled, we get
![$m_1 * m_2=-1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rkyijh2qzzzvyo3hhhyj4lx4evrz0vxow6.png)
Therefore, product of slopes of the given lines are -1.
Hence, the line y = 7x + 2 perpendicular to the
.