Answer:
The probability that the student owns a car given that the student drives to school is 0.8
Explanation:
Lets put names to each variable
X = The student owns a car
Y = The student drives to school
We alredy know:
P(X) = 0.74
P(X ∪ Y) = 0.88
P(X ∩ Y) = 0.56
And we want to know P(X | Y)
Recall that P(X ∩ Y) = P(X|Y)*P(Y), and also
P(X ∪ Y) = P(X) + P(Y) - P(X∩Y)
Thus,
P(Y) = P(X ∪ Y) - P(X) + P(X ∩ Y) = 0.88-0.74+0.56 = 0.70
And
P(X|Y) = P(X ∩ Y)/P(Y) = 0.56/0.70 = 0.8
Therefore, the probability that the student owns a car given that the student drives to school is 0.8