Answer:
The remainder is 55
Explanation:
Let
![p(x)= 2 {x}^(4) + {x}^(2) - 10x - 1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bbqxmkuuj42inr524wgphmue6sftbbe2st.png)
According to the remainder theorem, if p(x) is divided by x+a, the remainder is p (-a).
The given divisor is x+2, therefore the remainder is given by:
![p( - 2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/snua5bvj2pj8meen4k57mtkbw441ij3ba6.png)
We substitute x=-2 to get:
![p( - 2)= 2 {( - 2)}^(4) + {( - 2)}^(2) - 10( - 2) - 1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cb88ivgikftytoa97uu4k8s6y2qmpdixvh.png)
We simplify to obtain:
![p( - 2)= 2 * 16 + 4 + 20- 1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bkyf84w2f3mc0v4khd8allgxck0n7d1du5.png)
We multiply to get:
![p( - 2)=3 2 + 4 + 20- 1 = 55](https://img.qammunity.org/2021/formulas/mathematics/middle-school/62z414sc44om24shxzsjcl0sawev1e0bp9.png)
Therefore the remainder is 55