Question

30) Shayna and Nicole are selling pies for a school fundraiser. Customers can buy apple pies and blackberry pies. Shayna sold 7 apple pies and 2 blackberry pies for a total of $148. Nicole sold 7 apple pies and 4 blackberry pies for a total of $184. What is the cost each of one apple pie and one blackberry pie?

A) apple pie: $18, blackberry pie: $16

B) apple pie: $18, blackberry pie: $14

C) apple pie: $25, blackberry pie: $27

D) apple pie: $16, blackberry pie: $18

Answer 1

Shayna and Nicole are selling pies for a school fundraiser. Customers can buy apple pies and blackberry pies. Shayna sold 7 apple pies and 2 blackberry pies for a total of $148. Nicole sold 7 apple pies and 4 blackberry pies for a total of $184- so the cost of the (D) apple pie: $16, blackberry pie: $18

Explanation:

Let A = the price of an apple pie and let B = the price of a blackberry pies. Using the information in the question we get two equations:

7A + 2B = $148======>(i)

7A + 4B = $184=======>(ii)

Making use of the Elimination Method . We multiply the bottom equation by -1 and then add the two equations together, we get:

7A + 2B = 148

-7A - 4B = -184

-2B = -36

B = 36/2=18

The cost of a blackberry pies is $18.

To find the cost of an apple pie, we simply substitute B = 18 in one of the equation.So choosing equation (i) we get

7A + 2(18) = 148

7A + 36 = 148

7A = 112

A = 16

The cost of an apple pie is $16