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Write the condition that Ix + my + n = 0 may be a tangent to the circle x²+y² + 2gx + 2fy +C =0



User Jflaga
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1 Answer

4 votes

Answer:


r= \frac { \sqrt{ {l}^(2) + {m}^(2) } }

Explanation:

The given circle has equation


{x}^(2) + {y}^(2) + 2gx + 2fy + c = 0

This circle has centre (-g,-f).

For the line


lx + my + n = 0

to be a tangent to this circle, the perpendicular distance from the center to this line must be equal to the radius of the circle.

This is given by:


d = \frac { \sqrt{ {a}^(2) + {b}^(2) } }

We substitute the center and radius to get:


r=\frac { \sqrt{ {l}^(2) + {m}^(2) } }

We simplify to get;


r= \frac { \sqrt{ {l}^(2) + {m}^(2) } }

User Simon Thompson
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