1 Answer

Njol · Answer 1 · 2021-06-25T01:23:19+0000

(a) The product of
$(2x-4)\ and\ (3x^2-x+4)$ is calculated to be
=6x^3-14x^2+12x-16

(b)The product of
$(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of
$(4x-2)\ and\ (3x^2-x+4)$

Explanation:

(a)

$(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16$

b)

$(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8$

The product of
$(2x-4) \ and\ (3x^2-x+4)\$ is not equal to the product of
$(4x-2)\ and\ (3x^2-x+4)$

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