Question

Ask Your Teacher A coil is formed by winding 260 turns of insulated 16 gauge copper wire (diameter = 1.3 mm) in a single layer on a cylindrical form of radius 15 cm. What is the resistance of the coil? Neglect the thickness of the insulation.

Answer 1

The resistance is
`2.98`Ω

Step-by-step explanation:

Data

diameter:
`d=1.3mm`,
`d=1.3*10^(-3) m`

Radius:
`r=(d)/(2) ,r=(1.3*10^(-3) )/(2) ,r=6.5*10^(-4) m`

Resistivity constant:
`p=1.65*10^(-8)`Ω
`m`

To find Area:

`A=\pi r^(2) \\A=(22)/(7) *(6.5*10^(-4) )\\A=1.33*10^(-6) m^(2)`

To find circumference:

`l=260*(2\pi (0.15))\\l=245.04m`

Now we can apply the Resistivity formula:

`R=p(l)/(A)`

`R=(1.65*10^(-8) )`Ω
`m*(240.04m)/(1.33*10^(-6)m^(2) )`

`R=2.98`Ω