Question

What are the factors of x2 – 4x – 5? Check all that apply.

x – 5
x – 2
x – 1
x + 1
x + 2
x + 5

Answer 1

A. and D.

on edge

Explanation:

Answer 2

The the factors of
`x^2-4x-5` are (x+1) and (x-5)

Explanation:

Considering the expression

`x^2-4x-5`

`\mathrm{Break\:the\:expression\:into\:groups}`

`=\left(x^2+x\right)+\left(-5x-5\right)`

`\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2+x\mathrm{:\quad }x\left(x+1\right)`

`\mathrm{Factor\:out\:}-5\mathrm{\:from\:}-5x-5\mathrm{:\quad }-5\left(x+1\right)`

`=x\left(x+1\right)-5\left(x+1\right)`

`\mathrm{Factor\:out\:common\:term\:}x+1`

`=\left(x+1\right)\left(x-5\right)`

Therefore, the the factors of
`x^2-4x-5` are (x+1) and (x-5)