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Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400 mm wide. The diffraction pattern is observed on a screen 3.10 m away. Define the width of a bright fringe as the distance between the minima on either side.

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4 votes

Answer:


x=4.906nm

Step-by-step explanation:

Data

wavelength: ∧=
633nm
∧=0.633um

slit: a=
0.400mm
a= 400mm


R=3.10m

To find tita(angle):

sin(Tita)=∧/a


sin(tita)=(0.633um)/(400um) \\sin(Tita)=0.0015825\\Tita=sin^(-1) (0.0015825)

Tita=0.09°

distance between the minima on either side:


x=R*tan(Tita)\\x=(3.10m)*tan(0.09)\\x=3.10m*0.0015825\\x=0.004906m\\x=4.906nm

User Mrudult
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