Question

uncle leo turnes an old-fashion radio that has an antenna that is made from a 3.0-cm-long solenoid with a cross-sectional area of 0.50cm^2, composed of 300 turns of fine copper wire. Calculate the inductance of the coil assuming it is air-filled

Answer 1

L = 1.26 μH

Step-by-step explanation:

Length of the solenoid, l = 3.0 cm = 0.03 m

Cross sectional area of the solenoid, A = 0.50 cm² = 0.5 * 10⁻⁴ m²

A = 5 * 10⁻⁵ m²

N = 300 turns

The inductance of a coil is given by
`L = (2 \mu NA)/(l)`...................(1)

Magnetic constant,
`\mu = 4\pi * 10^(-7) H/m`

Substituting the appropriate values into equation (1)

`L = (2 *(4\pi*10^(-7)) * 300* 5 * 10^(-5) )/(0.03)\\L = 0.00000126 H\\L = 1.26 * 10^(-6) H\\ L = 1.26 microHenry`