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Find the value of X.
(√32)²= (X+2)²+x​

Find the value of X. (√32)²= (X+2)²+x​-example-1

2 Answers

6 votes
What the dude said above me ^^^ lol
User Keith Thompson
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3 votes

Answer:

Answer:x=−6.274917217635375,1.2749172176353745

Explanation:

(3(2))2=(x+2)2+x12=x2+5x+4

Step 1: Subtract x^2+5x+4 from both sides.12−(x2+5x+4)=x2+5x+4−(x2+5x+4)−x2−5x+8=0

For this equation: a=-1, b=-5, c=7.999999999999998−1x2+−5x+8=0Step 2: Use quadratic formula with a=-1, b=-5, c=7.999999999999998.x=−b±b2−4ac2ax=−(−5)±(−5)2−4(−1)(8)2(−1)x=5±57−2x=−6.274917217635375,1.2749172176353745

User Rommel
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