Answer:

Explanation:
Given Equations:
Equation:1
Equation:2
Solving Equation:2 for the value of 'y'

Subtracting '5x' both sides:
Equation:3
Using substitution method: Put the value of 'y' in equation:1


Subtracting '51' both sides:

Putting the value of 'x' in equation:3


The values of 'x' and 'y' are:
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