Answer:
Car A is 1.8-1.2= 0.6 times faster than car B
So the distance between them is changing 0.6 times faster.
Step-by-step explanation:
Car A is traveling north at 90km/hr and 0.3 km away from intersection point.
Car b is traveling west at 80km/hr and 0.4 km away from the intersection point.
The time it will take to get to intersection point by those two cars is how fast it is changing.
For car A
Time = distance/speed
Time = 0.3/90
Time = 3.333*10^-3
Time = 3.333*10^-3 hrs
Converting to seconds
(3.333*10^-3)*360= 1.199998
Approximately 1.2 seconds
For car B
Time = distance/time
Time= 0.4/80
Time = 5*10^-3
Time= 5*10^-3 hrs
Converting to seconds
(5*10^-3)*360= 1.8 seconds
Comparing the two times,
Car A is 1.8-1.2= 0.6 times faster than car B