Question

The specific heat of copper is 0.385 J/(g °C). If 34.2 g of copper, initially at 25°C, absorbs 4.689 kJ, what will be the

final temperature of the copper?

Answer 1

Answer: T = 381 °C

Explanation: Use the formula of heat or Q = mc∆T, where ∆T = ( T final - T initial).

First convert kJ into Joules.

4.689 kJ x 1000 J / 1 kJ

= 4,689 J

Derive for the final temperature.

T final = Q / ( mc ) + T initial

= 4689 J / 34.2 g ( 0.385 J/g°C) + 25°C

= 381 °C