Question

The sum of the digits of a 2-digit number is 11. If the digits are reversed, the number formed is 45 more than the original number. Find the original number. If x is the ten's digit and y is the one's digit, the original number is 10x+y. the number with reversed digits is 10y+x.

Answer 1

Answer:shoo ion kno

Step-by-step explanation:

Answer 2

The original number is 38

Step-by-step explanation:

Let the sum of the digits of a 2 digit number is 11.

If the digits are reversed, the number formed is 45 more than the original number.

Let x and y be the two numbers and
`x+y=11`

Let the original number be
`10x+y`

Let the reversed number be
`10y+8`

We need to determine the original number.

Original number:

We need to determine the original number
`10x+y`

Thus, we have,

`x+y=11` -----(1)

`(10x+y)+45=10y+x` --------(2)

Solving the equation (2), we get,

`10x+y+45-10y-x=0`

`9x-9y=-45`

`9(x-y)=-45`

`x-y=-5` --------(3)

Adding the equations (1) and (3), we get,

`2x=6`

`x=3`

Thus, the value of x is 3

Substituting
`x=3` in equation (1), we get,

`3+y=11`

`y=8`

Thus, the value of y is 8.

The equation of the original number is
`10x+y`

Substituting the value of x and y, we get,

Original number =
`10(3)+8\implies 30+8=38`

Thus, the original number is 38.