Question

A reaction vessel contains 2.50 moles of ci2 and 6.15 moles of f2 how many moles of excess reactant are left

Answer 1

2.4moles

Step-by-step explanation:

Number of moles of Cl₂ = 2.50moles

Number of moles of F₂ = 6.15moles

Unknown:

Moles of excess reactant left = ?

Solution:

The reaction equation:

Cl₂ + 3F₂ → 2ClF₃

Now, we need to find the excess reactant;

2 mole of chlorine gas combined with 3 mole of fluorine gas;

2.5 moles of chlorine gas will combine with
`(2.5 x 3)/(2)` = 3.75moles of F₂

The given number of moles of F₂ is 6.15moles

But the reaction needs 3.75 moles

The amount of excess reactant left = 6.15 - 3.75 = 2.4moles