Answer:
45(a + 2b)
Explanation:
45a
step1 in order to factor an integer, we need to repeatedly divide it by the ascending sequence of primes (2, 3, 5...) The number of times that each prime divides the original integer becomes its exponent in the final result
Prime number 3 to the power of 2 equals 9 .
Prime number 5 to the power of 1 equals 5 .
90b
do the same as above
Prime number 2 to the power of 1 equals 2 .
Prime number 3 to the power of 2 equals 9 .
Prime number 5 to the power of 1 equals 5 .