Option C:
![\left(\begin{array}{cc}-6 & 0 \\12 & 21\end{array}\right)](https://img.qammunity.org/2021/formulas/mathematics/college/y536uhzxrzfiqcrm1h7yz1o7d7j7xyida3.png)
Solution:
Given data:
![3\left[\begin{array}{cc}-2 & 0 \\4 & 7\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/vdbf8n98tradh2taf95g9euepyuxsiwsn7.png)
To find the product:
Scalar element = 3
Scalar multiplication:
Multiply each of the matrix element by a scalar.
Here multiply each of the matrix element by 3.
![3\left(\begin{array}{cc}-2 & 0 \\4 & 7\end{array}\right)=\left(\begin{array}{ccc}3(-2) & 3 \cdot 0 \\3 \cdot 4 & 3 \cdot 7\end{array}\right)](https://img.qammunity.org/2021/formulas/mathematics/college/rt1i3re1hx3z9hp8447mb4s71g2c8ilwho.png)
Simplifying each element, we get
![=\left(\begin{array}{cc}-6 & 0 \\12 & 21\end{array}\right)](https://img.qammunity.org/2021/formulas/mathematics/college/99ot24ceanz4z42mjb9y9bubwlrjx8srlm.png)
The value of the given matrix is
.
Option C is the correct answer.