Answer: 72 = 2^3 * 3^2
72 is even so 2 is a factor ; 72/3 = 36
36 and 36/2 = 18 are also even so we have two more 2’s as prime factors. 18/2 = 9 = 3*3 hence we have two 3’s as prime factors
Therefor the prime factors of 72 are 2*2*2*3*3 or 2^3*3^2
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