Question

A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 17 m/s at an angle θ = 27 ° below horizontal. The stone moves without air resistance; use a Cartesian coordinate system with the origin at the stone's initial position.

With what speed, vf in meters per second, does the stone strike the ground?

Answer 1

The stone strikes the ground in 14.71m/s

Step-by-step explanation:

The initial vertical velocity of the stone is given by:

Vyo= VSin theta

Given: V = 17m/s , theta = 27°

Vyo = 17 Sin 27

Vyo = 7.72m/s

Final vertical velocity, Vf can be determined by using kinematic equation

Vf^2 - U^2 = 2as

Vf^2 -( 7.72)^2 = 2(9.8×(-8))

Vf^2 = 59.60 + 156.8

Vf^2 = 216.4

Vf = sqrt(216.4)

Vf = 14.71m/s