Given,
- Diameter of the circle = 7 yd
- Have to take the value of π as 3.14
![\:](https://img.qammunity.org/2023/formulas/mathematics/college/2ggh1nmemdo9eckwr4kv18nc6ebnpn2pop.png)
To Find,
- The area and the circumference of a circle.
![\:](https://img.qammunity.org/2023/formulas/mathematics/college/2ggh1nmemdo9eckwr4kv18nc6ebnpn2pop.png)
Solution :
- As, the diameter is 7 yd, therefore the radius will be 3.5 yd
First of all, we'll find the circumference of the circle :
![\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Circumference_((circle)) = 2 \pi r}}}}}} \: \: \bigstar \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/fynhug41nujlgrr45img7yvedjjqxt3kw0.png)
Now, we'll substitute the required values in the formula :
![\\ { \longrightarrow \qquad{ \sf{ \: \: Circumference_((circle)) = 2 * 3.14 * 3.5}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/rcycvbukpj6nzrxdjkudvkcql37053an18.png)
![{ \longrightarrow \qquad{ \sf{ \: \: Circumference_((circle)) = 3.14 * 7}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/fhqceewjyrwv2641cv9zsuhbgcp7qc1otn.png)
![{ \longrightarrow \qquad{ \sf{ \pmb{ \: Circumference_((circle)) = 21.98}}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/z83yvqpiiym6uzmnw9eslcor00hhz2zzn1.png)
Therefore,
- The circumference of the circle is 21.98 yd
![\:](https://img.qammunity.org/2023/formulas/mathematics/college/2ggh1nmemdo9eckwr4kv18nc6ebnpn2pop.png)
Now, we'll find the area of the circle :
![\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Area_((circle)) = \pi r^2}}}}}} \: \: \bigstar \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/wjptvjg9muhaxtkrguhr9hs6u7mlutrrwl.png)
![{ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_((circle)) = 3.14 * { * (3.5)}^(2) }}}}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/uj8mb50nb0ekzt0gi34o9ty2d1w95pknp8.png)
![{ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_((circle)) = 3.14 * { * 3.5 * 3.5 }}}}}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/buurdshnf1awf488uvp5n2fwebjagi0lid.png)
![{ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_((circle)) = 3.14 * 12 .25 }}}}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/976zvytz4tmsdqnx38vyabvez9s2hleci4.png)
![{ \longrightarrow \qquad{ {{\pmb { \sf{ \: \: Area_((circle)) = 38.465 }}}}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/unx09r9q5upb6qx1rbuto9oofee41ud61w.png)
Therefore,
- The area of the circle is 38.46 yd² approximately