Answer:
The minimum sample size that should be taken is 24.
Explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so

Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.
If we want to be 95% confident that the sample mean is within 2 points of the true population mean, what is the minimum sample size that should be taken
This is n when







The minimum sample size that should be taken is 24.