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Write the equation of the line with a slope of 4/3 and passes through (6, 10)

1 Answer

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Answer:

y=4/3x+2

Explanation:

An equation in slope-intercept form is y=mx+b, so you can plug in x, y, and m.

x=6, y=10, m=4/3

10=4/3(6)+b

Multiply 4/3 and 6 to get 24/3, which is equal to 8

10=8+b

Subtract 8 from both sides

2=b

Now you know that b=2, so

t=4/3x+2

User Cameron Sparr
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