Answer:
93.18% probability that they have a mean height between 62.9 inches and 64.0 inches.
Explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sample means with size n of at least 30 can be approximated to a normal distribution with mean
and standard deviation

In this problem, we have that:

If 90 women are randomly selected, find the probability that they have a mean height between 62.9 inches and 64.0 inches.
This is the pvalue of Z when X = 64 subtracted by the pvalue of Z when X = 62.9. So
X = 64

By the Central Limit Theorem



has a pvalue of 0.9357
X = 62.9



has a pvalue of 0.0039
0.9357 - 0.0039 = 0.9318
93.18% probability that they have a mean height between 62.9 inches and 64.0 inches.