51.0k views
2 votes
Assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 90 women are randomly selected, find the probability that they have a mean height between 62.9 inches and 64.0 inches.

1 Answer

3 votes

Answer:

93.18% probability that they have a mean height between 62.9 inches and 64.0 inches.

Explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the zscore of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean
\mu and standard deviation
\sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean
\mu and standard deviation
s = (\sigma)/(√(n))

In this problem, we have that:


\mu = 63.6, \sigma = 2.5, n = 90, s = (2.5)/(√(90)) = 0.2635

If 90 women are randomly selected, find the probability that they have a mean height between 62.9 inches and 64.0 inches.

This is the pvalue of Z when X = 64 subtracted by the pvalue of Z when X = 62.9. So

X = 64


Z = (X - \mu)/(\sigma)

By the Central Limit Theorem


Z = (X - \mu)/(s)


Z = (64 - 63.6)/(0.2635)


Z = 1.52


Z = 1.52 has a pvalue of 0.9357

X = 62.9


Z = (X - \mu)/(s)


Z = (62.9 - 63.6)/(0.2635)


Z = -2.66


Z = -2.66 has a pvalue of 0.0039

0.9357 - 0.0039 = 0.9318

93.18% probability that they have a mean height between 62.9 inches and 64.0 inches.

User Darian Hickman
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.