Question

The hypotenuse of a right triangle measures 16 cm and one of its legs measures 9 cm. Find the measure of the other leg. If necessary, round to the nearest tenth.

Answer 1

`\sf\huge\underline{\star Solution:-}`

Given that:

• Hypotenuse of a right triangle =
  `\sf\blue{16cm.}`
• One side (leg) =
  `\sf\blue{9cm.}`

To Find:

• Measure of another side(leg).

Solution:-

`\rightarrow` As we know that,

`\sf{A^2 +B^2 \:=\: C^2}`(Pythagoras Theorem)

So, using this formula we can find measure of another side(leg).

`\rightarrow`
`\sf{A^2 +B^2 \:=\: C^2}`(putting the value of both given side of triangle)

• Here I am putting the value of hypotenuse in C because it is the longest side of triangle.

`\rightarrow`
`\sf{9^2 +B^2 \:=\: 16^2}`

`\rightarrow`
`\sf{81 +B^2 \:=\: 256}`

`\rightarrow`
`\sf{B^2 \:=\: 256-81}`

`\rightarrow`
`\sf{B^2 \:=\: 175}`

`\rightarrow`
`\sf{B \:=\: √(175)}`

`\rightarrow`
`\sf{B\:=\: 13.22(approx)}`

Therefore, measure of another side (leg) of the triangle =
`\sf\purple{ 13.22(approx).}`

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Hope it helps you:)