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Three beads are placed on the vertices of an equilateral triangle of side d = 3.6 cm. The first bead of mass m1 = 130 g is placed on the top vertex. The second bead of mass m2 = 55 g is placed on the left vertex. The third bead of mass m3 = 95 g is placed on the right vertex. show answer No Attempt 25% Part (a) Write a symbolic equation for the horizontal component of the center of mass relative to the left vertex of the triangle.

User Shobhu
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1 Answer

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Answer:

a)
\bar x = (d\cdot m_(3)+(d\cdot \cos 60^(\textdegree))\cdot m_(1))/(m_(1)+m_(2)+m_(3))

Explanation:

a) Let be origin set in the left vertex of the triangle and the horizontal axis is parallel to the side between the right and left beads. The horizontal component of the center of mass is:


\bar x = (d\cdot m_(3)+(d\cdot \cos 60^(\textdegree))\cdot m_(1))/(m_(1)+m_(2)+m_(3))

User TobKel
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