Answer:
The answer to your question is ΔHf = -114.2 kJ/mol
Step-by-step explanation:
Balanced chemical reaction
2NO(g) + O₂(g) ⇒ 2NO₂(g)
Standard heat of formation
ΔHf NO (g) = 90.3 kJ/mol
ΔHf O₂ (g) = 0.0 kJ/mol
ΔHf NO₂ (g) = 33.2 kJ/mol
- For this reaction
ΔHf = ∑ΔHf products - ∑Hf reactants
-Substitution
ΔHf = 2(33.2) - 2(90.3) - 0
-Simplification
ΔHf = 66.4 - 180.6
-Result
ΔHf = -114.2 kJ/mol