Question

On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about W/m². What is the electromagnetic energy contained in 5.20 m³ of space just above the earth's surface?

Answer 1

1.907 x 10⁻⁵ J.

Step-by-step explanation:

Given,

Volume of space, V = 5.20 m³

Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².

Electromagnetic energy = ?

`E = \mu V`

`E = ((S)/(c))* V`

where c is the speed of light.

`E = ((1.1* 10^3)/(3* 10^8))* 5.20`

`E = 1.907* 10^(-5)\ J`

Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.