Question

A 70.0-L steel tank at 20.0°C contains acetylene gas, C2H2, at a pressure of 1.39 atm. Assuming ideal behavior, how many grams of acetylene are in the tank? A 70.0-L steel tank at 20.0°C contains acetylene gas, C2H2, at a pressure of 1.39 atm. Assuming ideal behavior, how many grams of acetylene are in the tank? 4.04 g 105 g 12.9 g 1540 g

Answer 1

Answer: There are 105 grams of acetylene in the tank.

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 1.39 atm

V = volume of gas = 70.0 L

n = number of moles = ?

R = gas constant =
`0.0821Latm/Kmol`

T = temperature of gas in Kelvin =
`20.0^0C=(20.0+273)K=293.0K`

`1.39 atm* 70.0 L=n* 0.0821 L atm/K mol* 293.0K`

`n=4.04`

Mass of ethylene , M = Moles × Molar mass = 4.04 mole × 26 g/mol =105g

Thus there are 105 grams of acetylene in the tank.