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A bicycle wheel rotates at a constant 25 rev/min. What is true about its angular acceleration?

User Lee Wise
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1 Answer

1 vote

Answer:

The angular acceleration is zero

Step-by-step explanation:

When an object is in rotational motion, it has a certain angular velocity, which is the rate of displacement of its angular position.

This angular velocity can change or remain constant - this is given by the angular acceleration, which is:


\alpha =(\Delta \omega)/(\Delta t)

where


\Delta \omega is the change in angular velocity


\Delta t is the time elapsed

Therefore, the angular acceleration is the rate of change of angular velocity.

In this problem, the bicycle rotates at a constant angular velocity of


\omega=25 rev/min

This means that the change in angular velocity is zero:


\Delta \omega=0

And so, that the angular acceleration is zero:


\alpha=0

User Supergentle
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