Answer:
38.40% probability that it would take between 2.5 and 3.5 hours to construct a soapbox derby car.
Explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 3, \sigma = 1](https://img.qammunity.org/2021/formulas/mathematics/college/ewnmoywtvnxn2svvins3o8l5m9n36l9mhb.png)
Find the probability that it would take between 2.5 and 3.5 hours to construct a soapbox derby car.
This is the pvalue of Z when X = 3.5 subtracted by the pvalue of Z when X = 2.5
X = 3.5
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
![Z = (3.5 - 3)/(1)](https://img.qammunity.org/2021/formulas/mathematics/college/q4j7fpklw068s0fzcs2yhz6ea0y290orsl.png)
![Z = 0.5](https://img.qammunity.org/2021/formulas/mathematics/college/twz22bn6gf92fta2hvttsmn1vzvc38s68o.png)
has a pvalue of 0.6915
X = 2.5
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
![Z = (2.5 - 3)/(1)](https://img.qammunity.org/2021/formulas/mathematics/college/30ukrvdgrmomsqodt3kff02xqu075sskc1.png)
![Z = -0.5](https://img.qammunity.org/2021/formulas/mathematics/college/brhv8qpekwycdpd8ao7few4wdvdrpb5gsz.png)
has a pvalue of 0.3075
0.6915 - 0.3075 = 0.3840
38.40% probability that it would take between 2.5 and 3.5 hours to construct a soapbox derby car.