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Trigonometry

Objective: Use trigonometry functions to find the area of triangles.
In ΔABC, AB=21, AC=16, and m< A=67*. Find the area of ΔABC, to the nearest tenth of a square unit.

User Uggeh
by
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1 Answer

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The area of the triangle ABC is 154.6 square units

Step-by-step explanation:

Given that the measurements of the sides of the triangles are
AB=21 ,
AC=16 and
m\angle A=67^(\circ)

We need to determine the area of the triangle ABC

Area of triangle ABC:

The area of the triangle can be determined using the formula,


\text {Area}=(1)/(2) b c \sin A

Substituting the values, we get,


\text {Area}=(1)/(2)(21)(16) \sin 67^(\circ)

Simplifying the terms, we get,


\text {Area}=(1)/(2)(21)(16) (0.92)

Multiplying the values, we have,


\text {Area}=(309.12)/(2)

Dividing, we get,


\text {Area}=154.56

Rounding off to the nearest tenth, we get,


Area = 154.6

Thus, the area of the triangle ABC is 154.6 square units

User Joe Eng
by
8.3k points
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