Final answer:
Acid J is 100 times more acidic than acid K.
Step-by-step explanation:
The pH of acid J is 4 and the pH of acid K is 6. To determine how much more acidic acid J is than acid K, we can look at the difference in their pH values. The pH scale is logarithmic, so a difference of one unit represents a tenfold difference in acidity. Therefore, acid J is (10^(pH of acid K - pH of acid J)) = **100 times** more acidic than acid K.