Question

A rectangle has a height of 4 and a width of 2x^2-x

Answer 1

Perimeter:
`4x^2-2x+8`

Area:
`8x^2-4x`

Explanation:

I will assume the question asks for perimeter and area of the rectangle with given dimensions.

The height is "4"

The width (assuming) is "
`2x^2-x`"

First, the perimeter:

Perimeter is sum of all 4 sides of a rectangle, so we have 2 widths and 2 lengths, we sum them up:

`Perimeter=4+2x^2-x+4+2x^2-x=4x^2-2x+8`

Now, the area:

Area is the height times width, so it will be:

`Area=4*(2x^2-x)=8x^2-4x`