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The coordinates of the points bellow represent the vertices of a rectangle: P: (2,2). Q:(6,2) R:(6,5) S:(2,5) What is the perimeter, in units, of rectangle PQRS

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Answer:

Therefore the value of perimeter of the rectangle is 14 in.

Explanation:

The opposite sides of a rectangle are congruent.

The perimeter of a rectangle is 2(length + width)

The area of a rectangle is (length×width).

Given the vertices of a rectangle are P(2,2), Q(6,2), R(6,5) and S(2,5).

To find the the perimeter, first we need the sides of the rectangle.

The distance between two points(x₁,y₁) and (x₂,y₂) is


=√((x_2-x_1)^2+(y_2-y_1)^2)

The distance between P and Q is


=√((6-2)^2+(2-2)^2) in


=\sqrt {4^2+0^2} in

=4 in

The distance between Q and R is


=\sqrt{(6-6)^2+(5-2)^2 in


=√(0^2+3^2) in

=3 in

The distance between R and S is


=√((2-6)^2+(5-5)^2) in


=√( (-4)^2) in

=4 in

The distance between S and P is


=√((2-2)^2+(2-5)^2) in


=√((-3)^2) in

=3 in

Therefore the length of the rectangle is = 4 in.

an the width of the rectangle is = 3 in

Therefore the perimeter of the rectangle is =2(4+3) in

=14 in

User Osmond Bishop
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