Question

A window in a submersible needs to be able to withstand the incredible forces that water will exert at depth. If the window is 30 cm x 15 cm, what would the force exerted by the water be at a depth of 1 km

Answer 1

`F=441000\ N`

Step-by-step explanation:

Given:

dimension of the window,
`(30* 15)\ cm`

depth of window under water,
`d=1000\ m`

We know that the pressure due to liquid column is given as:

`P=\rho.g.d`

where:

`\rho=` density of water

`g=` acceleration due to gravity

`d=` depth of the water column at the desired position

`P=1000* 9.8* 1000`

`P=9800000\ Pa`

Now the force acting on the area of the window:

`F=P.A`

where:

`A=` area of the window

`F=9800000* (0.3* 0.15)`

`F=441000\ N`

Answer 2

Step-by-step explanation:

Area of the window, A = 30 cm x 15 cm = 0.045 m²

depth, h = 1 km = 1000 m

Let P is the pressure

P = h x d x g

where d is the density of water

P = 1000 x 1000 x 9.8 = 9.8 x 10^6 Pa

Force, F = Pressure x Area

F = 9.8 x 10^6 x 0.045

F = 4.41 x 10^5 N