Answer:
Riemann sum
W = lim n→∞ Σ 0.4xᵢΔx (with the summation done from i = 1 to n)
Workdone in pulling the entire rope to the top of the building = 180 lb.ft
Work done in pulling half the rope to the top of the building = 135 lb.ft
Step-by-step explanation:
Using Riemann sum which is an estimation of area under a curve
The portion of the rope below the top of the building from x to (x+Δx) ft is Δx.
Then workdone in lifting this portion through a length xᵢ ft would be 0.4xᵢΔx
So, the Riemann sum for this total work done would be
W = lim n→∞ Σ 0.4xᵢΔx (with the summation done from i = 1 to n)
The Riemann sum can easily be translated to integral form.
In integral form, with the rope being 30 ft long, we have
W = ∫³⁰₀ 0.4x dx
W = [0.2x²]³⁰₀ = 0.2 (30²) = 180 lb.ft
b) When half the rope is pulled to the top of the building, 30 ft is pulled up until the length remaining is 15 ft
W = ∫³⁰₁₅ 0.4x dx
W = [0.2x²]³⁰₁₅ = 0.2 (30² - 15²) = 135 lb.ft
Hope this Helps!!!