Given Information:
Total units = 1500
Defect free units = 1477
Required Information:
six-sigma performance = ?
Answer:
six-sigma performance:
DPU = 0.0153333
DMPU = 15333.33
Step-by-step explanation:
The six sigma is measure of quality enhancement in the organizations. There are six levels 1 to 6 where 1 represents lowest quality level and 6 represents highest quality level .
No. of defective units = total no. of units - defect free units
No. of defective units = 1500 - 1477
No. of defective units = 23
Defects per unit (DPU) is given by
DPU = No. of defective units/total no. of units
DPU = 23/1500
DPU = 0.0153333
DPU = 1.53 %
Defects per million units (DMPU) is given by
DMPU = DPU*1 million
DMPU = 0.0153333*1,000,000
DMPU = 15333.33
For six-sigma level DMPU must be equal or less than 3.4.
15333.33 is way more than 3.4 so the performance is not that great!